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(3x-2)(5x-4)=(3x-2)^2
We move all terms to the left:
(3x-2)(5x-4)-((3x-2)^2)=0
We multiply parentheses ..
(+15x^2-12x-10x+8)-((3x-2)^2)=0
We calculate terms in parentheses: -((3x-2)^2), so:We get rid of parentheses
(3x-2)^2
15x^2-12x-10x-((3x-2)^2)+8=0
We calculate terms in parentheses: -((3x-2)^2), so:We add all the numbers together, and all the variables
(3x-2)^2
15x^2-22x-((3x-2)^2)+8=0
We calculate terms in parentheses: -((3x-2)^2), so:
(3x-2)^2
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(3x-2)^2
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(3x-2)^2
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(3x-2)^2
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(3x-2)^2
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(3x-2)^2
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(3x-2)^2
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(3x-2)^2
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(3x-2)^2
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(3x-2)^2
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(3x-2)^2
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(3x-2)^2
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(3x-2)^2
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(3x-2)^2
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(3x-2)^2
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(3x-2)^2
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(3x-2)^2
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(3x-2)^2
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(3x-2)^2
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(3x-2)^2
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(3x-2)^2
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